Area type of a place is calculated based on population density, home ownership, and proximity to various amenties
Seymour town, WI
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About Seymour town
Seymour town is a suburb in the Appleton Metro Area and in the Outagamie County. It has a population of 1,411 and a population density of 40, which is 57% below the national average. It has a median age of 46, which is 7 years above the Appleton Metro median age and 8 years above the national average.
Seymour town has a median home value of $233,300, which is 12% below the Metro average.The average rent of $1,500 is 46% above the metro average rent and 29% above the national average rent. The average household income in Seymour town is $74,940 , which is 6% above the Metro average household income and 13% above the national average of household income.
The average school rating in Seymour town is 4. Seymour town also has a crime index 43 that is below the Metro average and below the National average.
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Seymour town Zip Code
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Demographics
Seymour town's population is made up of 62% married, 23% single, 10% divorced and 5% widowed. Baby Boomers make up the largest percentage of the population at 44%, while Millennials have the second largest segment at 23%. Homeowners make up 80% of the population in Seymour town.
- 50% Male
- 50% Female
Employment
The Per Capita income in Seymour town is $31,961. The Median Household Income is $74,940 and the Seymour town Unemployment Rate is 1%.